The correct order of bond dissociation enthalpy of halogens is
The correct order of bond dissociation enthalpy of halogens is
Option 1 - <p>Cl<sub>2</sub> > Br<sub>2</sub> > F<sub>2</sub> > I<sub>2</sub> </p>
Option 2 - <p>Cl<sub>2</sub> > F<sub>2</sub> > Br<sub>2</sub> > I<sub>2</sub> </p>
Option 3 - <p>I<sub>2</sub> > Br<sub>2</sub> > Cl<sub>2</sub> > F<sub>2</sub> </p>
Option 4 - <p>F<sub>2</sub> > Cl<sub>2</sub> > Br<sub>2</sub> > I<sub>2</sub></p>
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6 months ago
Correct Option - 1
Detailed Solution:
Bond dissociation enthalpy is the energy required to break 1 mole of bond according to experimental data
Bond energy : Cl2 > Br2 > F2 > l2
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