The correct order of intensity of colors of the compounds is:

Option 1 -

${[N i C l_{4}]}^{2 -} > {[N i {(H_{2} O)}_{6}]}^{2 +} > {[N i {(C N)}_{4}]}^{2 -}$

Option 2 -

${[N i C l_{4}]}^{2 -} > {[N i {(C N)}_{4}]}^{2 -} > {[N i {(H_{2} O)}_{6}]}^{2 +}$

Option 3 -

${[N i {(H_{2} O)}_{6}]}^{2 +} > {[N i C l_{4}]}^{2 -} > {[N i {(C N)}_{4}]}^{2 -}$

Option 4 -

${[N i {(C N)}_{4}]}^{2 -} > {[N i C l_{4}]}^{2 -} > {[N i {(H_{2} O)}_{6}]}^{2 +}$

2 Views | Posted 2 months ago

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 1

Detailed Solution:

For Ni²⁺, crystal field CFSE magnitude shows the magnitude of absorbed light. Following are the energy absorbed order

${[N i C l_{4}]}^{2 -} < {[N i (H_{2} O)]}^{2 +} < {[N i {(C N)}_{4}]}^{2 -}$

Hence order of colour of compounds are.

${[N i C l_{4}]}^{2 -} > {[N i {(H_{2} O)}_{6}]}^{2 +} > {[N i {(C N)}_{4}]}^{2 -}$

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