The correct order of reduction potentials of the following pairs is A. Cl 2 /Cl- B. I2 / I- C. Ag+ / Ag D. Na+ / Na E. Li+ / Li

The correct order of reduction potentials of the following pairs is

A. Cl ₂/Cl^-

B. I₂/ I^-

C. Ag⁺ / Ag

D. Na⁺ / Na

E. Li⁺ / Li

Option 1 - Cl 2 /Cl-

Option 2 - I2 / I-

Option 3 - Ag+ / Ag

Option 4 - Na+ / Na

Option 5 - Li+ / Li

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Raj Pandey | Contributor-Level 9

6 months ago

Correct Option - 1

Detailed Solution:

$E_{C l_{2} / C l^{-}}^{0} = + 1.36 V$

$E_{l_{2} / l^{-}}^{0} = + 0.54 V$

$E_{A g^{+} / A g}^{0} = + 0.80 V$

$E_{N a^{+} / N a}^{0} = - 2.71 V$

$E_{L i^{+} / L i}^{0} = - 3.05 V$

$∴ E_{C l_{2} / C l^{-}}^{0} > E_{A g^{+} / A g}^{0} > E_{N a^{+} / N a}^{0} > E_{L i^{+} / L i}^{0}$

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