The correct statement about B₂H₆ is:

Correct Option - 1


Detailed Solution:

Angle of H_t – B – H_t > angle of H_b – B - H_b

Bond angle $\propto \mathrm{\%}S-Character\propto \frac{1}{\mathrm{\%}ofP-character}$  

$\angle H_t$ B H_t is more so % P-Character is less.

 

<div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1755068091php09UKBA.jpeg" alt="" width="555" height="210" loading="lazy"></picture></div></div><p>Angle of H_t – B – H_t &gt; angle of H_b – B - H_b</p><p>Bond angle<span contenteditable="false"> <math> <mrow> <mo>∝</mo> <mn>%</mn> <mi>S</mi> <mo>−</mo> <mi>C</mi> <mi>h</mi> <mi>a</mi> <mi>r</mi> <mi>a</mi> <mi>c</mi> <mi>t</mi> <mi>e</mi> <mi>r</mi> <mo>∝</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>%</mn> <mi>o</mi> <mi>f</mi> <mtext> </mtext> <mtext> </mtext> <mi>P</mi> <mo>−</mo> <mi>c</mi> <mi>h</mi> <mi>a</mi> <mi>r</mi> <mi>a</mi> <mi>c</mi> <mi>t</mi> <mi>e</mi> <mi>r</mi> </mrow> </mfrac> </mrow> </math> </span>&nbsp;&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1816593599"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;</p><p><span contenteditable="false"> <math> <mrow> <mo>∠</mo> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mi>t</mi> </mrow> </msub> </mrow> </math> </span>&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1026" DrawAspect="Content" ObjectID="_1816593600"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;B H_t is more so % P-Character is less.</p><p>&nbsp;</p>

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