The correct statement about B2H6 is:

Angle of Ht – B – Ht > angle of Hb – B - Hb Bond angle ∝ % S − C h a r a c t e r ∝ 1 % o f P − c h a r a c t e r ∠ H t B Ht is more so % P-Character is less.

The correct statement about B₂H₆ is:

Option 1 - All B – H – B angles are of 120°.

Option 2 - The two B – H – B bonds are not of same length.

Option 3 - Its fragment, BH3, Behaves as a Lewis base.

Option 4 - Terminal B – H bonds have less p – character when compared to bridging bonds.

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Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 1

Detailed Solution:

Angle of Ht – B – Ht > angle of Hb – B - Hb

Bond angle $\propto % S - C h a r a c t e r \propto \frac{1}{% o f P - c h a r a c t e r}$ $\frac{}{}$

$_{}$ $∠ H_{t}$ B Ht is more so % P-Character is less.

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Chemistry Ncert Solutions Class 11th 2023

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