Solid State Class 12th Chemistry NCERT Exemplar Solutions Class 11th Chapter Four Chemistry Ncert Solutions Chemistry Class 12th

**The distance between Na+ and Cl ions in solid NaCl of density 43.1g cm3 is ________*1010m. (Nearest Integer)**

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Raj Pandey | Contributor-Level 9

5 months ago

$d = \frac{Z M}{N_{A} a^{3}} = \frac{4 * 58.5}{6.02 * 1 0^{23} * a^{3}}$

$43.1 = \frac{4 * 58.5}{6.02 * 1 0^{23} * a^{3}}$

$∴ a = 2.08 * 1 0^{- 8} c m$

$∴ r_{N a^{+}} + r_{C l^{-}} = 1.04 * 1 0^{- 10}$ m

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Four 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter Four 2025

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