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The effective atomic number of Fe in K4[Fe(CN)6] is

Option 1 -

35

Option 2 -

38

Option 3 -

36

Option 4 -

34

0 1 View | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 weeks ago
    Correct Option - 3


    Detailed Solution:

    EAN = Atomic No. – Oxidation state + 2 * CN

    = 26 – 2 + 2 * 6

    = 36.

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