The electronic configurations of three elements, A, B and C are given below. Answer the questions 14 to 17 on the basis of these configurations.

A

1S2 2S2  2P6

B

1S2 2S2  2P6 3S2 3P3

C

1S2 2S2  2P6 3S2 3P5

table form of A may be represented by the formula :

(i) A

(ii) A2

(iii) A3

(iv) A4

48 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
V
8 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Option (i)

The electronic configuration of A 1S2 2S2  2P6  is having no unpaired electrons in the outer most shells. So, an atom having no unpaired electron in its valence shell is said to be stable.

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

He2 has zero bond order hence it does not exist.

The three fundamental laws of chemistry are - Law of Definite Proportions, Law of Conservation of Mass, and Law of Multiple Proportions.

The three types of chemical bonds are - ionic, metallic and covalent bonds. When the electrons transfer between the atoms, they form the Ionic bonds by producing charged ions that are attracted to each other. When atoms share electrons, covalent bonds are created. When metal atoms share a sea of del

...Read more

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry NCERT Exemplar Solutions Class 11th Chapter Four 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter Four 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering