The energy of one mole of photons of radiation of wavelength 300nm is (Given: h = 6.63 * 10³⁴ Js,N_A = 6.02 * 10²³ mol^-1 c = 3 * 10⁸ ms^-1)

Option 1 - 235 kJ mol-1

Option 2 - 325 kJ mol-1

Option 3 - 399 kJ mol-1

Option 4 - 435 kJ mol-1

3 Views|Posted 5 months ago

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Raj Pandey | Contributor-Level 9

5 months ago

Correct Option - 3

Detailed Solution:

Energy of 1 photon = $\frac{h c}{λ}$

Energy of 1 mole of photon = $N_{A} * \frac{h c}{λ}$

$= \frac{6.022 * 1 0^{23} * 6.63 * 1 0^{- 34} * 3 * 1 0^{8}}{300 * 1 0^{- 9}}$

=0.399 * 10⁶ J = 399KJ

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The energy of one mole of photons of radiation of wavelength 300nm is (Given: h = 6.63 * 1034 Js,NA = 6.02 * 1023 mol-1 c = 3 * 108 ms-1)

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