The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O2 for complete oxidation and produces 4 times its own volume of CO2 is CxHy. The value of y is…………….

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Chemistry Hydrocarbon Chemistry Class 11th Hydrocarbons

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O₂for complete oxidation and produces 4 times its own volume of CO₂ is C_xH_y. The value of y is…………….

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Vishal Baghel | Contributor-Level 10

a month ago

$C_{x} H_{y} (g) + (x + \frac{y}{4}) O_{2} (g) \to x C O_{2} (g) + \frac{y}{2} H_{2} O (l)$

V 6V - -

- - 4V

Volume of CO2 = 4 × $V_{C_{x} H_{y}}$ $_{_{}_{}}$

Vx = 4V

x = 4

Volume of O2 = 6 × $V_{C_{x} H_{y}}$ $_{_{}_{}}$

$V (x + \frac{y}{4}) = 6 V$

$4 + \frac{y}{4} = 6$

y = 8

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The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O₂for complete oxidation and produces 4 times its own volume of CO₂ is C_xH_y. The value of y is…………….

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