The IUPAC name of the following compound is:

Option 1 - <p>4-Bromo-5-methylcyclopentanoic acid</p>
Option 2 - <p>4-Bromo-2-methylcyclopentane carboxylic acid</p>
Option 3 - <p>3-Bromo-5- methylcyclopentane carboxylic acid</p>
Option 4 - <p>&nbsp;5-Bromo-3-methylcyclopentanoic acid(GOC)</p>
3 Views|Posted 6 months ago
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6 months ago
Correct Option - 2
Detailed Solution:

Correct IUPAC name is 4-Bromo-2-methylcyclopentane carboxylic acid

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ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

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