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The Ksp for bismuth sulphide (Bi2S3) is 1.08 × 1073. The solubility of Bi2S3 in mol L1 at 298 K is

Option 1 -

1.0 * 1015

Option 2 -

2.7 * 1012

Option 3 -

3.2 *1010

Option 4 -

4.2 * 108

0 4 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    3 months ago
    Correct Option - 1


    Detailed Solution:

    B i 2 S 3 ? 2 B i 2 S + 3 + 3 S 3 S − 2

    K s p = ( 2 S ) 2 ( 3 S ) 3 = 4 × 2 7 × ( S ) 5

    = 108 (S)5

    ( S ) 5 = 1 . 0 8 × 1 0 − 7 3 1 0 8 = 1 0 − 7 5 ∴ S = 1 0 − 1 5 M

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