The limiting molar conductivities of Nal, NaNO3 and AgNO3 are 12.7, 12.0 and 13.3 mS m2 mol-1, respectively (all at 25°C). The limiting molar conductivity of Agl at this temperature is_________mS m2 mol-1.

<!- [if gte mso 9]><xml> </xml><! [endif]-> λ m ∞ of Nal = 12.7 mSm2 mol-1 λ m ∞ of NaNO3 = 12.0 m Sm2 mol-1 λ m ∞ of AgNO3 = 13.3 mSm2 mol-1 ∴ λ A g l ∞ = [ λ m ∞ ( A g N O 3 ) + λ m ∞ ( N a l ) ] − λ m ∞ N a N O 3 <!- [if gte mso 9]><xml> </xml><! [endif]-> = (13.3 + 12.7) - 12.0 = 14.0 m Sm2 mol-1

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Chemistry Class 12th Chemistry Electrochemistry

The limiting molar conductivities of Nal, NaNO₃ and AgNO₃ are 12.7, 12.0 and 13.3 mS m² mol^-¹, respectively (all at 25°C). The limiting molar conductivity of Agl at this temperature is_________mS m² mol^-¹.

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alok kumar singh | Contributor-Level 10

3 months ago

$λ_{m}^{\infty}$ of Nal = 12.7 mSm² mol^-1

$λ_{m}^{\infty}$ of NaNO₃ = 12.0 m Sm² mol^-1

$λ_{m}^{\infty}$ of AgNO₃ = 13.3 mSm² mol^-1

$∴ λ_{A g l}^{\infty} = [λ_{m}^{\infty} (A g N O_{3}) + λ_{m}^{\infty} (N a l)] - λ_{m}^{\infty} N a N O_{3}$

= (13.3 + 12.7) - 12.0 = 14.0 m Sm² mol^-1

<!- [if gte mso 9]><xml> <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1815380731"> </o:OLEObject></xml><! [endif]-> <math> <mrow> <msubsup> <mrow> <mi>λ</mi> </mrow> <mrow> <mi>m</mi> </mrow> <mrow> <mo>∞</mo> </mrow> </msubsup> </mrow> </math>  of Nal = 12.7 mSm2 mol-1 <math> <mrow> <msubsup> <mrow> <mi>λ</mi> </mrow> <mrow> <mi>m</mi> </mrow> <mrow> <mo>∞</mo> </mrow> </msubsup> </mrow> </math> of NaNO3 = 12.0 m Sm2 mol-1 <math> <mrow> <msubsup> <mrow> <mi>λ</mi> </mrow> <mrow> <mi>m</mi> </mrow> <mrow> <mo>∞</mo> </mrow> </msubsup> </mrow> </math> of AgNO3 = 13.3 mSm2 mol-1 <math> <mrow> <mo>∴</mo> <msubsup> <mrow> <mi>λ</mi> </mrow> <mrow> <mi>A</mi> <mi>g</mi> <mi>l</mi> </mrow> <mrow> <mo>∞</mo> </mrow> </msubsup> <mo>=</mo> <mrow> <mo> [</mo> <mrow> <msubsup> <mrow> <mi>λ</mi> </mrow> <mrow> <mi>m</mi> </mrow> <mrow> <mo>∞</mo> </mrow> </msubsup> <mrow> <mo> (</mo> <mrow> <mi>A</mi> <mi>g</mi> <mi>N</mi> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> </mrow> <mo>)</mo> </mrow> <mo>+</mo> <msubsup> <mrow> <mi>λ</mi> </mrow> <mrow> <mi>m</mi> </mrow> <mrow> <mo>∞</mo> </mrow> </msubsup> <mrow> <mo> (</mo> <mrow> <mi>N</mi> <mi>a</mi> <mi>l</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mo>]</mo> </mrow> <mo>−</mo> <msubsup> <mrow> <mi>λ</mi> </mrow> <mrow> <mi>m</mi> </mrow> <mrow> <mo>∞</mo> </mrow> </msubsup> <mi>N</mi> <mi>a</mi> <mi>N</mi> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> </mrow> </math>              <!- [if gte mso 9]><xml> <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1028" DrawAspect="Content" ObjectID="_1815380734"> </o:OLEObject></xml><! [endif]-> = (13.3 + 12.7) - 12.0 = 14.0 m Sm2 mol-1

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The limiting molar conductivities of Nal, NaNO₃ and AgNO₃ are 12.7, 12.0 and 13.3 mS m² mol^-¹, respectively (all at 25°C). The limiting molar conductivity of Agl at this temperature is_________mS m² mol^-¹.

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