The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:

**[Given: The threshold frequency of platinum is 1.3 * 10¹⁵s^-¹ and h = 6.6 * 10^-³⁴ J s.]**

Option 1 - 3.21 × 10-14 J

Option 2 - 6.24 × 10-16 J

Option 3 - 8.58 × 10-19

Option 4 - 9.76 × 10-20 J

2 Views|Posted 8 months ago

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Raj Pandey | Contributor-Level 9

8 months ago

Correct Option - 3

Detailed Solution:

$?_{0} = h υ_{0}$

$= 6.6 * 1 0^{- 34} * 1.3 * 1 0^{15} J$

^{$= 8.58 * 1 0^{- 19} J$}

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The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is 1.3 * 1015s-1 and h = 6.6 * 10-34 J s.]

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