The molar conductance of NaCl, HCl and CH?COONa at infinite dilution are 126.45, 426.16 and 91.0 cm² mol¯¹ respectively. The molar conductance of CH?COOH at infinite dilution is. Choose the right option for your answer.

Option 1 - <p>201.28Scm² mol⁻¹<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>390.71Scm² mol⁻¹</p>
Option 3 - <p>698.28Scm² mol⁻¹</p>
Option 4 - <p>540.48 S cm² mol⁻¹</p>
2 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 2
Detailed Solution:

Λ°m (NaCl) = 126.45Scm² mol? ¹
Λ°m (HCl) = 426.16Scm² mol? ¹
Λ°m (CH? COONa) = 91Scm² mol? ¹
Λ°m (CH? COOH) =Λ°m (CH? COONa) +Λ°m (HCl)−Λ°m (NaCl)
= 91 + 426.16 – 126.45
= 391.72Scm² mol? ¹

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