<p><strong>The number of molecules with energy greater than the threshold energy for a reaction increases five fold by a rise of temperature from <math><msup><mrow><mrow><mn>27</mn></mrow></mrow><mrow><mrow><mo>∘</mo></mrow></mrow></msup><mi mathvariant="normal">C</mi></math> to <math><msup><mrow><mrow><mn>42</mn></mrow></mrow><mrow><mrow><mo>∘</mo></mrow></mrow></msup><mi mathvariant="normal">C</mi></math> . Its energy of activation in <math><mi mathvariant="normal">J</mi><mo>/</mo><mi mathvariant="normal">m</mi><mi mathvariant="normal">o</mi><mi mathvariant="normal">l</mi></math> is (Take in <math><mn>5</mn><mo>=</mo><mn>1.6094</mn><mo>;</mo><mi mathvariant="normal">R</mi><mo>=</mo><mn>8.314</mn><mtext></mtext><mi mathvariant="normal">J</mi><msup><mrow><mrow><mtext></mtext><mi mathvariant="normal">m</mi><mi mathvariant="normal">o</mi><mi mathvariant="normal">l</mi></mrow></mrow><mrow><mrow><mo>-</mo><mn>1</mn></mrow></mrow></msup><msup><mrow><mrow><mtext></mtext><mi mathvariant="normal">K</mi></mrow></mrow><mrow><mrow><mo>-</mo><mn>1</mn></mrow></mrow></msup></math> )(Kinetics)</strong></p>

Sol. PT=XAPA0-PB0+PB0ATQ550=14PA0-PB0+PB02200=PA0-PB0+4PB0560=15PA0-PB0+PB02200=PA0-PB0+5PB0PA0+3PB0=2200PA0±4PB0=2800PB0=600PA0=400mmHg

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The number of molecules with energy greater than the threshold energy for a reaction increases five fold by a rise of temperature from $27^{\circ} C$ to $42^{\circ} C$ . Its energy of activation in $J / m o l$ is (Take in $5 = 1.6094; R = 8.314 J {m o l}^{- 1} K^{- 1}$ )(Kinetics)

3 Views | Posted 3 months ago

Answered by

alok kumar singh | Contributor-Level 10

3 months ago

Sol.

$P_{T} = X_{A} (P_{A}^{0} - P_{B}^{0}) + P_{B}^{0}$

ATQ

$550 = \frac{1}{4} (P_{A}^{0} - P_{B}^{0}) + P_{B}^{0}$

$2200 = P_{A}^{0} - P_{B}^{0} + 4 P_{B}^{0}$

$560 = \frac{1}{5} (P_{A}^{0} - P_{B}^{0}) + P_{B}^{0}$

$2200 = P_{A}^{0} - P_{B}^{0} + 5 P_{B}^{0}$

$P_{A}^{0} + 3 P_{B}^{0} = 2200$

$\frac{P_{A}^{0} \pm 4 P_{B}^{0} = 2800}{P_{B}^{0} = 600}$

$P_{A}^{0} = 400 m m H g$