Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Eight Redox Reactions Redox Reactions Chemistry Ncert Solutions Chemistry Class 11th

The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?

(i) The oxidation number of hydrogen is always +1.

(ii) The algebraic sum of all the oxidation numbers in a compound is zero.

(iii) An element in the free or the uncombined state bears oxidation number zero.

(iv) In all its compounds, the oxidation number of fluorine is – 1

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Alok Kumar Singh | Contributor-Level 10

9 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (i) is the correct answer

In ionic hydrides hydrogen exists in -1 oxidation state because the hydrogen acquires negative charge in the presence of its companion.

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How many of these compounds will undergo disproportionation on hydrolysis? CO?, NO?, Cl?, F?, ClO?, Cl?O?, N?O?, SO?, P?O??

$\overset{\overset{+ 4}{{N O}_{2}}}{2} + H_{2} O \to \overset{+ 3}{{H N O}_{2}} + \overset{+ 5}{H N O}_{3}$

$\overset{0}{{C l}_{2}} + H_{2} O \to \overset{- 1}{H C l} + H O C l$

$2 \overset{+ 4}{{C l O}_{2}} + H_{2} O \to \overset{+ 3}{{H C l O}_{2}} + \overset{+ 5}{{H C l O}_{3}}$

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40. Best reducing agent is:
(a) He (b) Be (c) Li (d) Al

Kindly go through the solution

(c) Li

37. Which element is considered to have oxidation number of +3 in all its compounds?

(a) Be (b) Li (c) Al (d) Sc

Kindly go through the solution

(c) Al

36. Oxidation number ofS in S₂O₈^-2is

(a) -2 (b) -6 (c) +2 (d) +6

Kindly go through the solution

(d) +6

32. Assertion: Na⁺ ion has an oxidation number of +1, Mg²⁺ ion, +2, Fe³⁺ion, +3, Cl^– ion, –1, O^2– ion, –2; and so on.

Reason: For ions composed of only one atom, the oxidation number is equal to the charge on the ion.

Kindly go through the solution

(a)

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Eight 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter Eight 2025

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