The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is _______ ×10-5 mol dm-3. (Round off to the nearest integer).
[ Given : Henry's law constant = KH = 8.0 ×104 kPa for O2. Density of water with dissolved oxygen = 1.0kg dm-3]

0 4 Views | Posted a month ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    Partial Pressure of O? = K? * solubility (K? = Henry's constant)
    Solubility = PO? / K? = 20 / (8.0 × 10? ) = 2.5 × 10? = 25 × 10? M
    Ans = 25

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