The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is _______ *10-5 mol dm-3. (Round off to the nearest integer).
[ Given : Henry's law constant = KH = 8.0 *104 kPa for O2. Density of water with dissolved oxygen = 1.0kg dm-3]
The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is _______ *10-5 mol dm-3. (Round off to the nearest integer).
[ Given : Henry's law constant = KH = 8.0 *104 kPa for O2. Density of water with dissolved oxygen = 1.0kg dm-3]
Partial Pressure of O? = K? * solubility (K? = Henry's constant)
Solubility = PO? / K? = 20 / (8.0 * 10? ) = 2.5 * 10? = 25 * 10? M
Ans = 25
Similar Questions for you
Correct order of van there Waals constant b for gases is CO2 > N2 > O2 > H2 > He
(A) Fluorspar – CaF2
(B) Cryolite – Na3 [AlF6]
Kindly go through the solution
Since VReal > Videal
So, Z = VReal > 1. Videal
The Answer is Maxwell? Boltzmann distribution
NH3 can be liquefied most easily due to presence of strong intermolecular H-bonding among NH3 molecules.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry Ncert Solutions Class 11th 2023
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering