The products obtained during treatment of hard water using Clark's method are:

Option 1 - CaCO3 and MgCO3

Option 2 - Ca(OH)2 and Mg(OH)2

Option 3 - CaCO3 and Mg(OH)2

Option 4 - Ca(OH)2 and MgCO3

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Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 3

Detailed Solution:

In Clark's method lime water is used

$\begin{array}{l} C a {(H C O_{3})}_{2} + 2 C a {(O H)}_{2} \to 2 C a C O_{3} + 2 H_{2} O \\ M g {(H C O_{3})}_{2} + 2 C a {(O H)}_{2} \to 2 C a C O_{3} + M g {(O H)}_{2} + 2 H_{2} O \end{array}$

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