The resistance of a conductivity cell containing 0.01 MKCl solution at 298K is . If is 0.152 * 10-3 cm-1, then the cell constant of the conductivity cell _________ * 10-3 cm-1.
The resistance of a conductivity cell containing 0.01 MKCl solution at 298K is . If is 0.152 * 10-3 cm-1, then the cell constant of the conductivity cell _________ * 10-3 cm-1.
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
Answered by
6 months ago
= 0.152 * 10-3 * 1750
= 266 * 10-3 cm-1
Upvote 
Similar Questions for you
ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
Rate of ESR ∝ No. of α – H (Hyperconjugation)
Cr3+ion is a most stable in aqueous solution due to. t2g half filled configuration
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Didn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering