The solubility product of a sparingly soluble salt A2X3 is 1.1 * 10-23. If specific conductance of the solution is 3 * 10-1, the limiting molar conductivity of the solution is x * 10-3 S m2 mol-1. The value of x is_________.

Using ; ksp = 108 S5 1.1 * 10-23 = 108 S5 S = ( 1 1 0 1 0 8 * 1 0 − 2 5 ) 1 / 5 M ≈ 1 0 − 5 M Specific conductance, λ m 0 = κ 5 * 1 0 0 0 S m 2 m o l − 1 = 3 * 10-3 Sm2 mol-1 So; x = 3

The solubility product of a sparingly soluble salt A₂X₃ is 1.1 * 10^-²³. If specific conductance of the solution is 3 * 10^-¹, the limiting molar conductivity of the solution is x * 10^-³ S m² mol^-¹. The value of x is_________.

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Raj Pandey | Contributor-Level 9

4 months ago

Using ; k_sp = 108 S⁵

1.1 * 10^-23 = 108 S⁵

S = ${(\frac{110}{108} * 1 0^{- 25})}^{1 / 5} M \approx 1 0^{- 5} M$

Specific conductance,

$λ_{m}^{0} = \frac{κ}{5 * 1000} S m^{2} m o l^{- 1}$

= 3 * 10^-3 Sm² mol^-1

So; x = 3

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