The total number of unpaired electrons present in is- $\left[Co{\left(N{H}_3\right)}_6\right]C{l}_{2}and\left[Co{\left(N{H}_3\right)}_6\right]C{l}_3$

NH₃ behaves as strong field ligand with Co²⁺ & Co³⁺

$\left[Co{\left(N{H}_3\right)}_6\right]C{l}_2$              

$C{o}^{2+}-4s^{0}3d^7$      

It has one unpaired electorn.

 $\left[Co{\left(N{H}_3\right)}_6\right]C{l}_3$

$C{o}^{3+}-4s^{0}3d^6$    

It has no unpaired electrons

So, total unpaired electrons in both compounds is 1.

 

<p>NH₃ behaves as strong field ligand with Co²⁺ &amp; Co³⁺</p><p><span contenteditable="false"> <math> <mrow> <mrow> <mo> [</mo> <mrow> <mi>C</mi> <mi>o</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>N</mi> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>6</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> <mi>C</mi> <msub> <mrow> <mi>l</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> </mrow> </math> </span> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1816177519"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;</p><p><span contenteditable="false"> <math> <mrow> <mi>C</mi> <msup> <mrow> <mi>o</mi> </mrow> <mrow> <mn>2</mn> <mo>+</mo> </mrow> </msup> <mo>−</mo> <mn>4</mn> <msup> <mrow> <mi>s</mi> </mrow> <mrow> <mn>0</mn> </mrow> </msup> <mn>3</mn> <msup> <mrow> <mi>d</mi> </mrow> <mrow> <mn>7</mn> </mrow> </msup> </mrow> </math> </span> &nbsp; &nbsp; &nbsp;</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1754652054phpyzKWz1.jpeg" alt="" width="676" height="69" loading="lazy"></picture></div></div><p>It has one unpaired electorn.</p><p><span contenteditable="false">&nbsp;<math> <mrow> <mrow> <mo> [</mo> <mrow> <mi>C</mi> <mi>o</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>N</mi> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>6</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> <mi>C</mi> <msub> <mrow> <mi>l</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> </mrow> </math> </span></p><p><span contenteditable="false"> <math> <mrow> <mi>C</mi> <msup> <mrow> <mi>o</mi> </mrow> <mrow> <mn>3</mn> <mo>+</mo> </mrow> </msup> <mo>−</mo> <mn>4</mn> <msup> <mrow> <mi>s</mi> </mrow> <mrow> <mn>0</mn> </mrow> </msup> <mn>3</mn> <msup> <mrow> <mi>d</mi> </mrow> <mrow> <mn>6</mn> </mrow> </msup> </mrow> </math> </span> &nbsp; &nbsp;</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1754652093phpj6zE9N.jpeg" alt="" width="502" height="79" loading="lazy"></picture></div></div><p>It has no unpaired electrons</p><p>So, total unpaired electrons in both compounds is 1.</p><p>&nbsp;</p>

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