Two compounds A and B with same molecular formula (C?H?O) undergo Grignard reaction with methylmagnesium bromide to give products C and D. Products C and D show following chemical tests. C and D respectively are:
gives iodoform test and slow Lucas test, so it's a methyl secondary alcohol. D gives fast Lucas test, so it's a tertiary alcohol. The Grignard products must be tertiary and secondary alcohols. So A and B must be an aldehyde and a ketone.
<p>gives iodoform test and slow Lucas test, so it's a methyl secondary alcohol. D gives fast Lucas test, so it's a tertiary alcohol. The Grignard products must be tertiary and secondary alcohols. So A and B must be an aldehyde and a ketone.</p><div class="photo-widget-full"><div class="figure"><picture><source srcset="" media="(max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1756123957phpAetmPh.jpeg" alt="" width="432" height="330" loading="lazy"></picture></div><div class="figure"><div class="photo-widget-full"><div class="figure"><picture><source srcset="" media="(max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1756124010phpih7HBo.jpeg" alt="" width="725" height="141" loading="lazy"></picture></div></div><p> </p></div></div><p> </p>
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