What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?

(i) 4 mol L–1

(ii) 20 mol L–1

(iii) 0.2 mol L–1

(iv) 2 mol L–1

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8 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (C)

No. of mole given = g i v e n m a s s m o l a r m a s s

On substituting the value in the above equation, the cal, can be calculated as

no, of mole =  5.85 g 58.5 g m o l - 1  = 0.1 g

The molarity (M) is given by the formula:

M = n V 1

On substituting the values in the above equation:

Mo

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Chemistry NCERT Exemplar Solutions Class 11th Chapter One 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter One 2025

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