Which of the following equations depicts the reducing nature of H2O2?
(i) 2[Fe(CN)6]4- + 2H+ + H2O2 → 2[Fe(CN)6]3- + 2H2O
(ii) I2 + H2O2 + 2OH–→ 2I-+ 2H2O + O2
(iii) Mn2+ + H2O2 → Mn4+ + 2OH
(iv) PbS + 4H2O2→ PbSO4 + 4H2O
Which of the following equations depicts the reducing nature of H2O2?
(i) 2[Fe(CN)6]4- + 2H+ + H2O2 → 2[Fe(CN)6]3- + 2H2O
(ii) I2 + H2O2 + 2OH–→ 2I-+ 2H2O + O2
(iii) Mn2+ + H2O2 → Mn4+ + 2OH
(iv) PbS + 4H2O2→ PbSO4 + 4H2O
This is a multiple choice answer as classified in NCERT Exemplar
Option (ii)
I2 + H2O2 + 2OH–→ 2I-+ 2H2O + O2
As iodine is reduced from 0 to -1.
Similar Questions for you
H2S has minimum boiling point.
PbS + 4H2O2->PbSO4 + 4H2O.
Volume strength of H2O2 = Molarity * 11.2
HF molecules are associated with strong intermolecular hydrogen bonding hence its boiling point is the highest
Compound Melting Point (K)
HF 190
HCl
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry NCERT Exemplar Solutions Class 11th Chapter Nine 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering
