Which of the following equations depicts the reducing nature of H2O2?
(i) 2[Fe(CN)6]4- + 2H+ + H2O2 → 2[Fe(CN)6]3- + 2H2O
(ii) I2 + H2O2 + 2OH–→ 2I-+ 2H2O + O2
(iii) Mn2+ + H2O2 → Mn4+ + 2OH
(iv) PbS + 4H2O2→ PbSO4 + 4H2O
Which of the following equations depicts the reducing nature of H2O2?
(i) 2[Fe(CN)6]4- + 2H+ + H2O2 → 2[Fe(CN)6]3- + 2H2O
(ii) I2 + H2O2 + 2OH–→ 2I-+ 2H2O + O2
(iii) Mn2+ + H2O2 → Mn4+ + 2OH
(iv) PbS + 4H2O2→ PbSO4 + 4H2O
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
Option (ii)
I2 + H2O2 + 2OH–→ 2I-+ 2H2O + O2
As iodine is reduced from 0 to -1.
Similar Questions for you
H2S has minimum boiling point.
PbS + 4H2O2->PbSO4 + 4H2O.
Volume strength of H2O2 = Molarity * 11.2
HF molecules are associated with strong intermolecular hydrogen bonding hence its boiling point is the highest
Compound Melting Point (K)
HF 190
HCl 159
HBr 185
HI
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