Which of the following options represents the correct bond order :
(i) O2– > O2 > O2+
(ii) O2 –
< O2
< O2 +
(iii) O2 – > O2 < O2+
(iv) O2–
< O2 > O2+
Which of the following options represents the correct bond order :
(i) O2– > O2 > O2+
(ii) O2 – < O2 < O2 +
(iii) O2 – > O2 < O2+
(iv) O2– < O2 > O2+
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (ii)
The electronic configurations and the bond orders of the given species are given below:
Bond order of O2 - : σ1s2 σ∗1s2 σ2s2 σ∗2s2 σ2p2z (π2p2x = π2p2y) (π∗2p1x= π∗2p1y)
Bond order = ( Nb- Na)
BO= (10-7)= = 1.5
Bond order of O2 + : σ1s2 σ∗1s2 σ2s2 σ∗2s2 σ2p2z (π2p2x = π2p2y) (π∗2p1x= π∗2p0y)
Bond order = (10-5)= =2.5
Bond order of O2 : σ1s2 σ∗1s2 σ2s2 σ∗2s2 σ2p2z (π2
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