Which of the following order of energies of molecular orbitals of N2 is correct? (i) (π2py ) (σ2pz ) > (π* 2px ) ≈ (π*2py ) (iii) (π2py ) (π* 2px) ≈ (π*2py ) (iv) (π2py ) > (σ2pz ) < (π* 2px ) ≈ (π*2py )

This is a Multiple Choice Questions as classified in NCERT Exemplar Ans: Option (iv) In the molecules of boron ( B2 ), carbon ( C2 ) and nitrogen ( N2 ) the energy of s2pz molecular orbital is greater than the energy of P2px and P2py molecular orbital. So, the correct order of energies of molecular orbital of N2 is (π2py ) > (σ2pz ) < (π* 2px ) ≈ (π*2py )

Which of the following order of energies of molecular orbitals of N₂ is correct?

(i) (π2p_y ) < (σ2p_z ) < (π* 2p^x) ≈ (π2p_y)

(ii) (π2p_y ) > (σ2p_z ) > (π 2p_x ) ≈ (π2p_y )

(iii) (π2p_y) < (σ2p_z ) > (π 2p_x) ≈ (π2p_y )

(iv) (π2p_y ) > (σ2p_z ) < (π 2p_x ) ≈ (π*2p_y )

14 Views|Posted 8 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Vishal Baghel | Contributor-Level 10

8 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Option (iv)

In the molecules of boron ( B₂), carbon ( C₂) and nitrogen ( N₂ ) the energy of s2p_z molecular orbital is greater than the energy of P2p_x and P2p_y molecular orbital.

So, the correct order of energies of molecular or