Which of the following pair is expected to have the same bond order?

(i) O2 , N2 

(ii) O2+, N2-

(iii) O2-, N2+

(iv) O2-,N2-

0 2 Views | Posted 3 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    This is a Long Answer Type Questions as classified in NCERT Exemplar

    Ans: Option (ii)

    (i) The electronic configuration of O2 is:

    σ1s2 σ∗1s2 σ2s2 σ∗2s2 s2pz2 π2p2y π2p2x π*2p1y π*2p1x

    Bond order = 1 2 ( Nb- Na)

    Bond order = 1 2 (10-6)=2.0

    The electronic configuration of N2 :

    σ1s2 σ*1s2 σ2s2 σ*2s2 π2p2x, π2p2y σ2p2z

    Bond order = 1 2 (10-4)=3.0

    So, the bond order of O2 , N2 will not be equal.

    (ii) The electronic configuration of O2+ is:

    σ1s2 σ∗1s2 σ2s2 σ∗2s2 s2pz2,π2p2y , π2p2x, π*2p1x

    Bond order = 1 2 (10-5)=2.5

    The electronic conf

    ...more

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