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Which of the following statement is incorrect?

Option 1 -

Low solubility of LiF in water is due to its small hydration enthalpy.

Option 2 -

KO2 is paramagnetic.

Option 3 -

Solution of sodium in liquid ammonia is conducting in nature.

Option 4 -

Sodium metal has higher density than potassium metal.

0 3 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago
    Correct Option - 1


    Detailed Solution:

    (a) low solubility of LiF in H2O due to high lattice energy.

    (b) O 2 −  has unpaired e- thus paramagnetic.

    (c) Na in liq NH3 forms electronated ammonia thus conducting in nature.

    (d) d K < d N a .

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