Which of the following statement is incorrect?

Option 1 - <p>Low solubility of LiF in water is due to its small hydration enthalpy.</p>
Option 2 - <p>KO<sub>2</sub> is paramagnetic.</p>
Option 3 - <p>Solution of sodium in liquid ammonia is conducting in nature.</p>
Option 4 - <p>Sodium metal has higher density than potassium metal.</p>
3 Views|Posted 6 months ago
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1 Answer
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6 months ago
Correct Option - 1
Detailed Solution:

(a) low solubility of LiF in H2O due to high lattice energy.

(b) O 2  has unpaired e- thus paramagnetic.

(c) Na in liq NH3 forms electronated ammonia thus conducting in nature.

(d) d K < d N a .

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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