‘x’ g of molecular oxygen(O2) is mixed with 200g of neon (Ne). The total pressure of the non-reactive mixture of O2 and Ne in the cylinder is 25 bar. The partial pressure of Ne is 20 bar at the same temperature and volume. The value of ‘x’ is_________.

Po2 = PTotal - <!- [if gte mso 9]><xml> </xml><! [endif]-> P N 2 5 = ( x / 3 2 x / 3 2 + 2 0 0 2 0 ) × 2 5 ⇒ x = 8 0 g m = 25 – 20 = 5barPo2 = <!- [if gte mso 9]><xml> </xml><! [endif]-> n O 2 n O 2 + n N e × P T o t a l 5 = ( x / 3 2 x / 3 2 + 2 0 0 2 0 ) × 2 5 ⇒ x = 8 0 g m <!- [if gte mso 9]><xml> </xml><! [endif]->

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States of Matter Ncert Solutions Chemistry Class 11th Chemistry Class 11th

‘x’ g of molecular oxygen(O₂) is mixed with 200g of neon (Ne). The total pressure of the non-reactive mixture of O₂ and Ne in the cylinder is 25 bar. The partial pressure of Ne is 20 bar at the same temperature and volume. The value of ‘x’ is_________.

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alok kumar singh | Contributor-Level 10

3 months ago

Po₂ = P_Total - $P_{N_{2}}$ $5 = (\frac{x / 32}{x / 32 + \frac{200}{20}}) \times 25 \Rightarrow x = 80 g m$

= 25 – 20 = 5bar

Po₂ = $\frac{n_{O_{2}}}{n_{O_{2}} + n_{N e}} \times P_{T o t a l}$

$5 = (\frac{x / 32}{x / 32 + \frac{200}{20}}) \times 25 \Rightarrow x = 80 g m$

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