Answer the questions on the basis of the information given below.

There are five friends P, Q, R, S and T. Two of them play table tennis while the other three play different games, viz. football, cricket and chess. One table tennis player and the chess player stay on the same floor while the other three stay on floors 2, 4 and 5. Two of the players are industrialists while the other three belong to different occupations viz. teaching, medicine and engineering. The chess player is the oldest while one of the table tennis players, who plays at the national level is the youngest. The other table tennis player who plays at the regional level is between the football player and the chess player in age. S is a regional player and stays on floor 2. Q is an engineer while P is the industrialist and plays tennis at the national level

What is the occupation of the chess player?

Option 1 -

Engineer

Option 2 -

Industrialist

Option 3 -

Doctor

Option 4 -

Teacher

0 1 View | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago
    Correct Option - 1


    Detailed Solution:

    Name

    Game

    Occupation

    Floor

    Age

    P

    Tennis

    Industrialist

    3

    the youngest (1)

    Q

    Chess

    Engineer

    3

    the oldest (5)

    R

    Football

     

     

    6

    S

    Tennis

     

    2

    4

    T

    Crickets

     

     

    2

    From the above table Q is chess player and she is engineer option (A) is correct.

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Vishal Baghel

(c)                                                                                                                                                                 

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the highest average is Rs. 136   

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Using the data from above question, the lowest average is Rs. 100.

V
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We get the following table of earnings:

Persons

Win Total

Average

P

36 * 150 + 14 * 100 = 6800

136

Q

34 * 150 + 21 * 100 = 7200

131

R

23 * 150 + 36 * 100 = 6850

116

S

30 * 150 + 30 * 100 = 6000

100

Now we can see that the largest difference

= Maximum – Minimum = Rs. 7500 – Rs. 6800

= Rs. 700

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IITs = 60; IIMS = 40   

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