A college stores data on students, showing their gender and performance, on a computer disc. Due to virus, some of the data is lost and only the following could be recovered.
Study the table carefully and answer the questions given below it.
Performance
Total
Average
Good
Excellent
Male
50
Female
96
Total
54
However, an expert committee arrived at the following conclusions
I. One-third of the male students were ‘average’.
II. 40% of the students were female.
III. Half the total numbers of students were ‘excellent’.
What fraction of total excellent students are female excellent students?
A college stores data on students, showing their gender and performance, on a computer disc. Due to virus, some of the data is lost and only the following could be recovered.
Study the table carefully and answer the questions given below it.
|
Performance |
Total |
||
Average |
Good |
Excellent |
||
Male |
|
|
50 |
|
Female |
|
|
|
96 |
Total |
|
54 |
|
|
However, an expert committee arrived at the following conclusions
I. One-third of the male students were ‘average’.
II. 40% of the students were female.
III. Half the total numbers of students were ‘excellent’.
What fraction of total excellent students are female excellent students?
Option 1 -
0.37
Option 2 -
0.58
Option 3 -
0.24
Option 4 -
0.60
-
1 Answer
-
Correct Option - 2
Detailed Solution:Total number of excellent students = 120
Number of female excellent students = 70
Required fraction
Similar Questions for you
Please find the answer below
From the 1st statement: B2 is now as old as B3 was in the past. Hence B2 is younger to B3 or B2 < B3. Also sometime in the past B1 was twice as old as B4. So B1 is elder to B4 or B1 > B4. B3 will be as old as B5 in future, hence B3 < B5. The second statement suggests: B1 > B6. B1 was as old as B7 in the past. Hence B1 > B7. B4 will be as old as B6 in future. Hence B6 > B4. B6 will be as old as B7 now in future. Hence B7 > B6. B7 was as old as B2, when B1 was as old as B7. Hence B1 = B2. Combining both the results, we get: and B5 > B3 > B2 = B1 > B7 > B6 > B4 (Note by B1 = B2, it is meant that they are of similar age group, not necessarily the same).
B5 is the eldest brother.
According to the information provided following arrangement will be obtained:
(K→ Kerala ; G → Goa ; D → Delhi)
Order according to height | Student | Belong | |||||||||
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| K | G | D |
× | × | × | × | × | × | × | √ | Arun | × | × | √ |
× | × | √ | × | × | × | × | × | Ajit | √ | × | × |
√ | × | × | × | × | × | × | × | Rohan | √ | × | × |
× | × | × | × | × | √ | × | × | Gajraj | × | √ | × |
× | √ | × | × | × | × | × | × | Ronit | × | × | √ |
× | × | × | × | √ | × | × | × | Shubham | √ | × | × |
× | × | × | × | × | × | √ | × | Sweety | × | √ | × |
× | × | × | √ | × | × | × | × | Lovely | × | √ | × |
Looking at the table given in the first question of the set, we get that Talwar lives on the sixth floor.
The data available is not enough to determine where Rubi belongs to. The given data is insufficient to answer the above question.
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