Bus route no. 256 has exactly six stops on its route. Any bus plying on this route starts from the initial position, then stops first at stop one and then stops at two, three, four, five, and six respectively. After the bus reaches stop six, the bus turns and returns to its initial position and repeats the cycle. Buses are not allowed to carry people on its return journey.
Following are the six stops – R1, R2, R3, R4, R5, and R6 in no particular order, Further, following observations have been made regarding the stops on this route:
Observation 1 – R5 is the third stop.
Observation 2 – R2 is the sixth stop.
Observation 3 – The stop R6 is the stop immediately after R4.
Observation 4 – R3 is the stop immediately before R1.
If R1 is the second stop on this route, which among the following must be the stop immediately before R2?
Bus route no. 256 has exactly six stops on its route. Any bus plying on this route starts from the initial position, then stops first at stop one and then stops at two, three, four, five, and six respectively. After the bus reaches stop six, the bus turns and returns to its initial position and repeats the cycle. Buses are not allowed to carry people on its return journey.
Following are the six stops – R1, R2, R3, R4, R5, and R6 in no particular order, Further, following observations have been made regarding the stops on this route:
Observation 1 – R5 is the third stop.
Observation 2 – R2 is the sixth stop.
Observation 3 – The stop R6 is the stop immediately after R4.
Observation 4 – R3 is the stop immediately before R1.
If R1 is the second stop on this route, which among the following must be the stop immediately before R2?
Option 1 -
R3
Option 2 -
R6
Option 3 -
R4
Option 4 -
R5
Similar Questions for you
(c)
the highest average is Rs. 136
Using the data from above question, the lowest average is Rs. 100.
We get the following table of earnings:
Persons | Win Total | Average |
P | 36 * 150 + 14 * 100 = 6800 | 136 |
Q | 34 * 150 + 21 * 100 = 7200 | 131 |
R | 23 * 150 + 36 * 100 = 6850 | 116 |
S | 30 * 150 + 30 * 100 = 6000 | 100 |
Now we can see that the largest difference
= Maximum – Minimum = Rs. 7500 – Rs. 6800
= Rs. 700
IITs = 60; IIMS = 40
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