Directions for question: Answer the questions on the basis of the information give below.
In an ancient game of trading “Pirate Bay”, 6 players took part. The game is played in a manner that the players select a port each and then they trade with each other. Everything that they sent out to other player is known as exports and anything that they receive from other players is known as imports. The table below shows details of imports and exports of between those six players. The entry corresponding to a particular row i and column j gives the total amount of exports by a player i to a player j in all the previous trade rounds. For example the entry in row 2 column 4 means P2 has exported to P4 a total of 58 times. Total number of times trade happens between two players will be = total exports of i + total exports of j = total imports of i + total imports of j.
P1
P2
P3
P4
P5
P6
P1
×
50
40
44
57
68
P2
35
×
35
58
43
59
P3
17
9
×
15
7
24
P4
70
32
28
×
68
35
P5
98
64
53
45
×
52
P6
35
25
57
62
35
×
If we draw a pie chart of total trade of P3, then what will be the angle made by the trade between P3 and P2?
Directions for question: Answer the questions on the basis of the information give below.
In an ancient game of trading “Pirate Bay”, 6 players took part. The game is played in a manner that the players select a port each and then they trade with each other. Everything that they sent out to other player is known as exports and anything that they receive from other players is known as imports. The table below shows details of imports and exports of between those six players. The entry corresponding to a particular row i and column j gives the total amount of exports by a player i to a player j in all the previous trade rounds. For example the entry in row 2 column 4 means P2 has exported to P4 a total of 58 times. Total number of times trade happens between two players will be = total exports of i + total exports of j = total imports of i + total imports of j.
|
P1 |
P2 |
P3 |
P4 |
P5 |
P6 |
P1 |
× |
50 |
40 |
44 |
57 |
68 |
P2 |
35 |
× |
35 |
58 |
43 |
59 |
P3 |
17 |
9 |
× |
15 |
7 |
24 |
P4 |
70 |
32 |
28 |
× |
68 |
35 |
P5 |
98 |
64 |
53 |
45 |
× |
52 |
P6 |
35 |
25 |
57 |
62 |
35 |
× |
If we draw a pie chart of total trade of P3, then what will be the angle made by the trade between P3 and P2?
Option 1 -
11.8° &
Option 2 -
15.5°
Option 3 -
17.3°
Option 4 -
Cannot be determined
-
1 Answer
-
Correct Option - 2
Detailed Solution:We need to find the total trade by P3 Total trade by P3 = total exports by P3 + total imports by P3. To find the total exports we will see the row of P3, those will be the total exports. While the imports will be the exports of others to P3, so if we see all the values of row of P3 then that will total up to his imports.
Total trade by P3 = (total exports) + (total imports)
= (17 + 9 + 15 + 7 + 24) + (40 + 35 + 28 + 53 + 57)
= 285
Now to find the total trade between P3 and P2 we will add the exports of P3 to P2 and exports of P2 to P3 (imports of P3 from P2). The value comes out to be = 9 + 35 = 44
As we know in a pie total angle is 360 de
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From the 1st statement: B2 is now as old as B3 was in the past. Hence B2 is younger to B3 or B2 < B3. Also sometime in the past B1 was twice as old as B4. So B1 is elder to B4 or B1 > B4. B3 will be as old as B5 in future, hence B3 < B5. The second statement suggests: B1 > B6. B1 was as old as B7 in the past. Hence B1 > B7. B4 will be as old as B6 in future. Hence B6 > B4. B6 will be as old as B7 now in future. Hence B7 > B6. B7 was as old as B2, when B1 was as old as B7. Hence B1 = B2. Combining both the results, we get: and B5 > B3 > B2 = B1 > B7 > B6 > B4 (Note by B1 = B2, it is meant that they are of similar age group, not necessarily the same).
B5 is the eldest brother.
According to the information provided following arrangement will be obtained:
(K→ Kerala ; G → Goa ; D → Delhi)
Order according to height | Student | Belong | |||||||||
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| K | G | D |
× | × | × | × | × | × | × | √ | Arun | × | × | √ |
× | × | √ | × | × | × | × | × | Ajit | √ | × | × |
√ | × | × | × | × | × | × | × | Rohan | √ | × | × |
× | × | × | × | × | √ | × | × | Gajraj | × | √ | × |
× | √ | × | × | × | × | × | × | Ronit | × | × | √ |
× | × | × | × | √ | × | × | × | Shubham | √ | × | × |
× | × | × | × | × | × | √ | × | Sweety | × | √ | × |
× | × | × | √ | × | × | × | × | Lovely | × | √ | × |
Looking at the table given in the first question of the set, we get that Talwar lives on the sixth floor.
The data available is not enough to determine where Rubi belongs to. The given data is insufficient to answer the above question.
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