Five friends – Umang, Viren, Xavier, Falak and Gagan collected gold on the sea shore. They collected a total of 100 gold.
None of them collected less than 10 gold each. No two among them collected the same number of gold. Following information is given regarding the number of gold with each one of them:
I. Umang collected the same number of gold as Viren and Xavier put together.
II. Xavier collected 3 more gold than the cube of an integer.
III. The number of gold collected by Umang was the square of an integer.
IV. The number of gold collected by Viren was the square of an integer.
V. The number of gold collected by Falak and Gagan are in the ratio 4 : 3.
What was the difference in the number of gold collected by Xavier and Falak?
Five friends – Umang, Viren, Xavier, Falak and Gagan collected gold on the sea shore. They collected a total of 100 gold.
None of them collected less than 10 gold each. No two among them collected the same number of gold. Following information is given regarding the number of gold with each one of them:
I. Umang collected the same number of gold as Viren and Xavier put together.
II. Xavier collected 3 more gold than the cube of an integer.
III. The number of gold collected by Umang was the square of an integer.
IV. The number of gold collected by Viren was the square of an integer.
V. The number of gold collected by Falak and Gagan are in the ratio 4 : 3.
What was the difference in the number of gold collected by Xavier and Falak?
Option 1 -
5
Option 2 -
7
Option 3 -
9
Option 4 -
11
-
1 Answer
-
Correct Option - 1
Detailed Solution:U – Umang
V – Viren
X – Xavier
F – Falak
G – Eagan
We have
U + V + X + F + G = 100
And each one of U, V, W, X, F, G? 10
U = V + X and 3Y = 4Z
Now, U, V, X, F, G? 10
Also, U = V + X
X = Cube + 3
V, U = Square
and F : G = 4 : 3
This is possible only when
U = 36, V = 25, X = 11, G = 12, F = 16
Similar Questions for you
(c)
the highest average is Rs. 136
Using the data from above question, the lowest average is Rs. 100.
We get the following table of earnings:
Persons | Win Total | Average |
P | 36 * 150 + 14 * 100 = 6800 | 136 |
Q | 34 * 150 + 21 * 100 = 7200 | 131 |
R | 23 * 150 + 36 * 100 = 6850 | 116 |
S | 30 * 150 + 30 * 100 = 6000 | 100 |
Now we can see that the largest difference
= Maximum – Minimum = Rs. 7500 – Rs. 6800
= Rs. 700
IITs = 60; IIMS = 40
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