Kamal, Lalman, Manish, Nishant, Praveen, Qadir, Raman, Sanjay, Umang and Waqar are the only ten members in a department. There is a proposal to form a team from within the members of the department, subject to the following conditions.
(i) A team must include exactly one among Praveen, Raman, and Sanjay.
(ii) A team must include either Manish or Qadir, but not both.
(iii) If a team includes Kamal, then it must also include Lalman, and vice versa.
(iv) If a team include one among Sanjay, Umang, and Waqar, then it must also include the other two.
(v) Lalman and Nishant cannot be members of the same team. Lalman and Umang cannot be members of the same team.
(vi) The size of a team is defined as the number of members in the team.
What is maximum number of students who play Chess and Boxing?
Kamal, Lalman, Manish, Nishant, Praveen, Qadir, Raman, Sanjay, Umang and Waqar are the only ten members in a department. There is a proposal to form a team from within the members of the department, subject to the following conditions.
(i) A team must include exactly one among Praveen, Raman, and Sanjay.
(ii) A team must include either Manish or Qadir, but not both.
(iii) If a team includes Kamal, then it must also include Lalman, and vice versa.
(iv) If a team include one among Sanjay, Umang, and Waqar, then it must also include the other two.
(v) Lalman and Nishant cannot be members of the same team. Lalman and Umang cannot be members of the same team.
(vi) The size of a team is defined as the number of members in the team.
What is maximum number of students who play Chess and Boxing?
Option 1 -
50
Option 2 -
70
Option 3 -
88
Option 4 -
None of these
-
1 Answer
-
Correct Option - 2
Detailed Solution:Student who play Kabaddi and Boxing is l + o + m + f = 12 + o + m + f = 70 when c = 0
Similar Questions for you
(c)
the highest average is Rs. 136
Using the data from above question, the lowest average is Rs. 100.
We get the following table of earnings:
Persons | Win Total | Average |
P | 36 * 150 + 14 * 100 = 6800 | 136 |
Q | 34 * 150 + 21 * 100 = 7200 | 131 |
R | 23 * 150 + 36 * 100 = 6850 | 116 |
S | 30 * 150 + 30 * 100 = 6000 | 100 |
Now we can see that the largest difference
= Maximum – Minimum = Rs. 7500 – Rs. 6800
= Rs. 700
IITs = 60; IIMS = 40
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