Mr. John has 5 children & he gives different pocket money to all of his 5 children to do 5 particular tasks viz. going for morning walk, Exercise, Completing their home work, Drinking Milk and Assisting in family work. A particular child can do only one task at a time and each task can be assigned to one child only. (The values are in $)
Children
1
2
3
4
5
Going for
Morning Walk
35
31
44
23
36
Exercise
48
42
57
35
37
Completing their Homework
28
55
52
38
44
Drinking Milk
55
21
26
37
42
Assisting in
Family work
26
35
34
51
47
If all the children increase the pocket money demanded by them for the tasks, then what will be the least amount for doing the task, keeping in mind that children 1, 2, 3, 4 and 5 increased the amount for the task by 50%?
Mr. John has 5 children & he gives different pocket money to all of his 5 children to do 5 particular tasks viz. going for morning walk, Exercise, Completing their home work, Drinking Milk and Assisting in family work. A particular child can do only one task at a time and each task can be assigned to one child only. (The values are in $)
Children |
1 |
2 |
3 |
4 |
5 |
Going for Morning Walk |
35 |
31 |
44 |
23 |
36 |
Exercise |
48 |
42 |
57 |
35 |
37 |
Completing their Homework |
28 |
55 |
52 |
38 |
44 |
Drinking Milk |
55 |
21 |
26 |
37 |
42 |
Assisting in Family work |
26 |
35 |
34 |
51 |
47 |
If all the children increase the pocket money demanded by them for the tasks, then what will be the least amount for doing the task, keeping in mind that children 1, 2, 3, 4 and 5 increased the amount for the task by 50%?
Option 1 -
$225
Option 2 -
$220.5
Option 3 -
$214.5
Option 4 -
Cannot be determined
-
1 Answer
-
Correct Option - 3
Detailed Solution:The answer can be obtained directly by increasing the answer in question 11 by 50%, as all the Children increase the cost by 50% and hence the total cost will increase by 50% only.
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From the 1st statement: B2 is now as old as B3 was in the past. Hence B2 is younger to B3 or B2 < B3. Also sometime in the past B1 was twice as old as B4. So B1 is elder to B4 or B1 > B4. B3 will be as old as B5 in future, hence B3 < B5. The second statement suggests: B1 > B6. B1 was as old as B7 in the past. Hence B1 > B7. B4 will be as old as B6 in future. Hence B6 > B4. B6 will be as old as B7 now in future. Hence B7 > B6. B7 was as old as B2, when B1 was as old as B7. Hence B1 = B2. Combining both the results, we get: and B5 > B3 > B2 = B1 > B7 > B6 > B4 (Note by B1 = B2, it is meant that they are of similar age group, not necessarily the same).
B5 is the eldest brother.
According to the information provided following arrangement will be obtained:
(K→ Kerala ; G → Goa ; D → Delhi)
Order according to height | Student | Belong | |||||||||
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| K | G | D |
× | × | × | × | × | × | × | √ | Arun | × | × | √ |
× | × | √ | × | × | × | × | × | Ajit | √ | × | × |
√ | × | × | × | × | × | × | × | Rohan | √ | × | × |
× | × | × | × | × | √ | × | × | Gajraj | × | √ | × |
× | √ | × | × | × | × | × | × | Ronit | × | × | √ |
× | × | × | × | √ | × | × | × | Shubham | √ | × | × |
× | × | × | × | × | × | √ | × | Sweety | × | √ | × |
× | × | × | √ | × | × | × | × | Lovely | × | √ | × |
Looking at the table given in the first question of the set, we get that Talwar lives on the sixth floor.
The data available is not enough to determine where Rubi belongs to. The given data is insufficient to answer the above question.
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