Parakrima band members are late for a concert in the evening. On their way, they come across a cracked bridge which has no lighting. The bridge is strong enough to hold at most two of them, and they have only one torch with them. Andy can get across the bridge in 2 minutes, Sandy takes 3 minutes, Kandy takes 6 minutes, but Mandy takes 9 minutes. Two band members together can move only as fast as the slower between the two, and one band member must be carrying the torch during the crossing. The band crosses the bridge in such a manner that the total time taken is minimum.
How many ways are there such that all can cross the bridge in minimum time?
Parakrima band members are late for a concert in the evening. On their way, they come across a cracked bridge which has no lighting. The bridge is strong enough to hold at most two of them, and they have only one torch with them. Andy can get across the bridge in 2 minutes, Sandy takes 3 minutes, Kandy takes 6 minutes, but Mandy takes 9 minutes. Two band members together can move only as fast as the slower between the two, and one band member must be carrying the torch during the crossing. The band crosses the bridge in such a manner that the total time taken is minimum.
How many ways are there such that all can cross the bridge in minimum time?
Option 1 -
1
Option 2 -
2
Option 3 -
3
Option 4 -
4
-
1 Answer
-
Correct Option - 2
Detailed Solution:Following are the possible ways in which Andy, Kandy, Mandy and Sandy can cross the bridge in minimum time.
Case I:
Journey
Men
Time
1 st trip
Andy, Sandy
3 min
Return
Andy, Sandy
2 min
2 nd trip
Kandy, Mandy
9 min
Return
Sandy
3 min
Final trip
Sandy, Andy
3 min
Total time
20 min
Case II:
Journey
Men
Time
1 st trip
Sandy
3 min
Return
Andy, Sandy
3 min
2 nd trip
Kandy, Mandy
9 min
Return
Andy
3 min
Final trip
Sandy, Andy
2 min
Total time
20 min
In total, there are 2 ways to do so.
Similar Questions for you
(c)
the highest average is Rs. 136
Using the data from above question, the lowest average is Rs. 100.
We get the following table of earnings:
Persons | Win Total | Average |
P | 36 * 150 + 14 * 100 = 6800 | 136 |
Q | 34 * 150 + 21 * 100 = 7200 | 131 |
R | 23 * 150 + 36 * 100 = 6850 | 116 |
S | 30 * 150 + 30 * 100 = 6000 | 100 |
Now we can see that the largest difference
= Maximum – Minimum = Rs. 7500 – Rs. 6800
= Rs. 700
IITs = 60; IIMS = 40
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