Some children were taking free throws at the basketball court in school during lunch break. Below are some facts about how many baskets these children shot.

I. Giana shot 8 baskets less than Amlia.

II. Drew and Raddix together shot 37 baskets.

III. Joanna shot 8 baskets more than Drew.

IV. Amlia shot 5 baskets more than Drew.

V.  Amlia and Giana together shot 40 baskets.

Which of the following statements is true?

Option 1 -

Drew and Joanna together shot 46 baskets.

Option 2 -

Giana shot 18 baskets and Raddix shot 21 baskets.

Option 3 -

Drew shot 3 more baskets than Raddix.

Option 4 -

Raddix and Joanna together shot 29 baskets.

0 2 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago
    Correct Option - 1


    Detailed Solution:

    According to given condition, we conclude:

    I.    Amlia – Giana = 8

    II.  Drew + Raddix = 37

    III. Joanna = Drew + 8

    IV. Amlia = Drew + 5

    V.  Amlia + Giana = 40

    Using (I) and (IV),

    Amlia = 24, Giana = 16

    Using (IV),

    Drew = 19

    Using (III),

    Joanna = 27

    Using (II),

    Raddix = 18

    Drew and Joanna = 19 + 27 = 46

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