Some children were taking free throws at the basketball court in school during lunch break. Below are some facts about how many baskets these children shot.

I. Giana shot 8 baskets less than Amlia.

II. Drew and Raddix together shot 37 baskets.

III. Joanna shot 8 baskets more than Drew.

IV. Amlia shot 5 baskets more than Drew.

V. Amlia and Giana together shot 40 baskets.

Which of the following statements is true?

Option 1 - Drew and Joanna together shot 46 baskets.

Option 2 - Giana shot 18 baskets and Raddix shot 21 baskets.

Option 3 - Drew shot 3 more baskets than Raddix.

Option 4 - Raddix and Joanna together shot 29 baskets.

2 Views|Posted 6 months ago

Asked by Shiksha User

1 Answer

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Answered by

Payal Gupta | Contributor-Level 10

6 months ago

Correct Option - 1

Detailed Solution:

According to given condition, we conclude:

I. Amlia – Giana = 8

II. Drew + Raddix = 37

III. Joanna = Drew + 8

IV. Amlia = Drew + 5

V. Amlia + Giana = 40

Using (I) and (IV),

Amlia = 24, Giana = 16

Using (IV),

Drew = 19

Using (III),

Joanna = 27

Using (II),

Raddix = 18

Drew and Joanna = 19 + 27 = 46

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Result/Players	P	Q	R	S
Won	23	18	10	16
Won	13	16	13	14
Lost	8	13	16	13
Lost	6	8	20	17