The following table gives year wise and course wise admission to a college.
Sports
2016
2017
2018
2019
2021
2022
Course 1
160
200
250
150
140
160
Course 2
40
80
95
100
110
130
Course 3
80
120
120
110
150
130
Course 4
70
90
50
30
60
80
Course 5
100
140
180
200
250
300
Course 6
10
10
20
10
10
10
Total
460
640
715
600
720
810
For which course the total admission for all the 6 years is closest to the total admission for any one of the years?
The following table gives year wise and course wise admission to a college.
Sports |
2016 |
2017 |
2018 |
2019 |
2021 |
2022 |
Course 1 |
160 |
200 |
250 |
150 |
140 |
160 |
Course 2 |
40 |
80 |
95 |
100 |
110 |
130 |
Course 3 |
80 |
120 |
120 |
110 |
150 |
130 |
Course 4 |
70 |
90 |
50 |
30 |
60 |
80 |
Course 5 |
100 |
140 |
180 |
200 |
250 |
300 |
Course 6 |
10 |
10 |
20 |
10 |
10 |
10 |
Total |
460 |
640 |
715 |
600 |
720 |
810 |
For which course the total admission for all the 6 years is closest to the total admission for any one of the years?
Option 1 -
Course 2
Option 2 -
Course 4
Option 3 -
Course 5
Option 4 -
Course 3
-
1 Answer
-
Correct Option - 4
Detailed Solution:Total admission for each course:
Course 2 = 40 + 80 + 95 + 100 + 110 + 130 = 555,
Course 5 = 100 + 140 + 180 + 200 + 250 + 300 = 234,
Course 4 = 14 + 18 + 10 + 6 + 12 + 16 = 1170,
Course 3 = 80 + 120 + 120 + 110 + 150 + 130 = 710.
Similar Questions for you
Please find the answer below
From the 1st statement: B2 is now as old as B3 was in the past. Hence B2 is younger to B3 or B2 < B3. Also sometime in the past B1 was twice as old as B4. So B1 is elder to B4 or B1 > B4. B3 will be as old as B5 in future, hence B3 < B5. The second statement suggests: B1 > B6. B1 was as old as B7 in the past. Hence B1 > B7. B4 will be as old as B6 in future. Hence B6 > B4. B6 will be as old as B7 now in future. Hence B7 > B6. B7 was as old as B2, when B1 was as old as B7. Hence B1 = B2. Combining both the results, we get: and B5 > B3 > B2 = B1 > B7 > B6 > B4 (Note by B1 = B2, it is meant that they are of similar age group, not necessarily the same).
B5 is the eldest brother.
According to the information provided following arrangement will be obtained:
(K→ Kerala ; G → Goa ; D → Delhi)
Order according to height | Student | Belong | |||||||||
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| K | G | D |
× | × | × | × | × | × | × | √ | Arun | × | × | √ |
× | × | √ | × | × | × | × | × | Ajit | √ | × | × |
√ | × | × | × | × | × | × | × | Rohan | √ | × | × |
× | × | × | × | × | √ | × | × | Gajraj | × | √ | × |
× | √ | × | × | × | × | × | × | Ronit | × | × | √ |
× | × | × | × | √ | × | × | × | Shubham | √ | × | × |
× | × | × | × | × | × | √ | × | Sweety | × | √ | × |
× | × | × | √ | × | × | × | × | Lovely | × | √ | × |
Looking at the table given in the first question of the set, we get that Talwar lives on the sixth floor.
The data available is not enough to determine where Rubi belongs to. The given data is insufficient to answer the above question.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers