Twelve people P1, P2, P3, P4, P5, P6, P7, P8, P9, P10, P11 and P12 are sitting around a rectangular table. The following information is known.

The table has 12 chairs numbered from 1 to 12. 6 seats on one side of the table and 6 on the opposite side. The chairs are arranged in such a way that chair number 1 is just opposite to 12, 6 is opposite to 7 and so on.

P1 is sitting opposite to P11 who is the only person sitting between P3 and P10. P5 is sitting opposite to P9 who is the only person sitting between P2 and P12. P6, sitting at chair number 1is diagonally opposite to P3 who is sitting opposite to P4

If P12 is sitting opposite to P8, then who is sitting opposite to P7?

Option 1 - P5 or P6

Option 2 - P10 or P6

Option 3 - P10 or P5

Option 4 - None of these

1 Views|Posted 7 months ago

Asked by Shiksha User

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Answered by

Payal Gupta | Contributor-Level 10

7 months ago

Correct Option - 2

Detailed Solution:

From the above 2 cases.

In case (I) if P12 is sitting opposite to P8 then P6 is sitting opposite to P7. In case (II) if P12 is sitting opposite to P8 then P10 is sitting opposite to P7.

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Direction for question 13 to 16: Go through the chart given below and solve the questions based on it.

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Direction for question 13 to 16: Go through the chart given below and solve the questions based on it.

Given below are the win loss histories of four tennis players in their career.

Result/Players

P

Q

R

S

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23

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Won

13

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Lost

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Lost

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As in the case above what is the lowest average prize money won per money won per match by any player?

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Direction for question 13 to 16: Go through the chart given below and solve the questions based on it.

Given below are the win loss histories of four tennis players in their career.

Result/Players

P

Q

R

S

Won

23

18

10

16

Won

13

16

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14

Lost

8

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Lost

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If a win carries an award of Rs. 150 and a loss carries of Rs. 100, what is the largest difference in prize money earned among the four?

Vishal Baghel

We get the following table of earnings:

Persons	Win Total	Average
P	36 * 150 + 14 * 100 = 6800	136
Q	34 * 150 + 21 * 100 = 7200	131
R	23 * 150 + 36 * 100 = 6850	116
S	30 * 150 + 30 * 100 = 6000	100

Now we can see that the largest difference

= Maximum – Minimum = Rs. 7500 – Rs. 6800

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During the given period, the total pass outs from IIMs as a ratio of total pass outs from IITs is

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Result/Players	P	Q	R	S
Won	23	18	10	16
Won	13	16	13	14
Lost	8	13	16	13
Lost	6	8	20	17