15. A factory manufacturers two types of screws, A and B. Each type of screw requires the use of two machines, an automatic and a hand operated. It takes 4 minutes on the automatic and 6 minutes on hand operated machines to manufacture a package of screw A, while it takes 6 minutes on automatic and 3 minutes on hand operated machines to manufacture a package of screws B. Each machine is available for at the most 4 hours on any day. The manufacturer can sell a package of screws A at a profit of ?. 7 and screws B at a profit of ?. 10. Assuming that he can sell all the screws he manufactures, how many packages of each type should the factory owner produce a day in order to maximize his profit? Determine the maximum profit.

2 Views|Posted 9 months ago
Asked by Shiksha User
1 Answer
V
9 months ago

Let the factory manufacture x screws of type A and y screws of type B on each day. Therefore,

x ≥ 0 and y ≥ 0

The given information can be compiled in a table as follows.

 

Screw A

Screw B

Availability

Automatic Machine (min)

4

6

4 * 60 =240

Hand Operated Machine (min)

6

3

4 * 60 =240

The profit on a package of screws A is Rs 7 and on the package of screws B is Rs 10. Therefore, the constraints are

4x + 6y  240

6x + 3y  240

Total profit, Z=7x +10y

The

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Maths Ncert Solutions class 12th 2026

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