2. Find the degree measures corresponding to the following radian measures
(i) (ii)-4 (iii)
(iv)
2. Find the degree measures corresponding to the following radian measures
(i) (ii)-4 (iii) (iv)
-
1 Answer
-
2. (i)
We know that radian= 180°,
Hence, radian= ×
= × = × ×180=
=39 0
= 39+ minute (as 1=60′)
=39°+22′+
=39°+22′+ (as 1′=60”)
=39°+22′+30”.
=39° 22′ 30”.
(ii) -4
We know that radian = 180°.
Hence: -4 radian = -4× = 4× = 4×180°× .
= -
=229 0
=229+
=229+5′+ .
=229°+5′+27″
=229° 5′27″
(iii) .
Solution: We know tha
...more
Similar Questions for you
16cos2θ + 25sin2θ + 40sinθ cosθ = 1
16 + 9sin2θ + 20sin 2θ = 1
+ 20sin 2θ = 1
– 9cos 2θ + 40sin 2θ = – 39
48tan2θ + 80tanθ + 30 = 0
24tan2θ + 40tanθ + 15 = 0
-> ,
So will be rejected as
Option (4) is correct.
12x =
is the solution of above equation.
Statement 1 is true
f(0) = – 1 < 0
one root lies in , one root is which is positive. As the coefficients are real, therefore all the roots must be real.
Statement 2 is false.
tan2 A = tan B tan C
It is only possible when A = B = C at x = 1
A = 30°, B = 30°, C = 30°
a = sin−1 (sin5) = 5 − 2π
and b = cos−1 (cos5) = 2π − 5
∴ a2 + b2 = (5 − 2π)2 + (2π − 5)2
= 8π2 − 40π + 50
sin 2 + tan 2 > 0
Let tan = x
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers