2. Minimise Z = – 3x + 4 y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0.
2. Minimise Z = – 3x + 4 y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0.
Minimize
Subject to
The corresponding equation of the given inequalities are
The graph is shown below.

The bounded region OABC is the feasible region with the corner points O (0,0), A (4,0), B (2,3), and C (0,4
The value of Z at these points are

Therefore, the minimum value of Z is -12 at (4,0).
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= -8 (-3 + k)
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. (ii)
by using property
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Given 2x + y – z = 3 . (i)
x – y – z = α . (ii)
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(i) x 2 – (ii) – (iii) – (1 + β) z = 3 - α
For infinite solution 1 + β
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Maths Ncert Solutions class 12th 2026
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