2. Minimise Z = – 3x + 4 y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0.

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9 months ago

Minimize z=3x+4y

Subject to x+2y8, 3x+2y12, x0, y0

The corresponding equation of the given inequalities are

x+2y=83x+2y=12x=0, y=0

x8+y4=1

x4+y6=1x=0, y=0

The graph is shown below.

The bounded region OABC is the feasible region with the corner points O (0,0), A (4,0), B (2,3), and C (0,4

The value of Z at these points are

Therefore, the minimum value of Z is -12 at (4,0).

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