2π – (sin⁻¹(4/5) + sin⁻¹(5/13) + sin⁻¹(16/65)) is equal to:
2π – (sin⁻¹(4/5) + sin⁻¹(5/13) + sin⁻¹(16/65)) is equal to:
Option 1 -
3π/2
Option 2 -
5π/2
Option 3 -
7π/4
Option 4 -
π/2
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:2π - (sin? ¹ (4/5) + sin? ¹ (5/13) + sin? ¹ (16/65)
= 2π - (tan? ¹ (4/3) + tan? ¹ (5/12) + tan? ¹ (16/63)
= 2π - (tan? ¹ (63/16) + tan? ¹ (16/63)
= 2π - π/2 = 3π/2
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