4. Minimise Z = 3x + 5y such that x + 3y ≥ 3, x + y ≥ 2, x, y ≥ 0.
4. Minimise Z = 3x + 5y such that x + 3y ≥ 3, x + y ≥ 2, x, y ≥ 0.
Minimize
Such that
The corresponding equation of the given inequalities are
The graph of the given inequalities is

The feasible region is unbounded. The corner points are
The values of Z at these corner points as follows.

As the feasible region is unbounded, 7 may or may not be minimum value of Z.
We dr
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. (ii)
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Given 2x + y – z = 3 . (i)
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Maths Ncert Solutions class 12th 2026
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