61. Give examples of two functions f: N → Z and g: Z → Z such that g o f is injective but g is not injective.
(Hint: Consider f(x) = x and g(x) = |x| )
61. Give examples of two functions f: N → Z and g: Z → Z such that g o f is injective but g is not injective.
(Hint: Consider f(x) = x and g(x) = |x| )
Define as and as
We first show that g is not injective.
It can be observed that:
is not injective.
Now, is defined as
Let such that
Since , both are positive.
Hence, gof is injective
Similar Questions for you
R1 = { (1, 1) (1, 2), (1, 3)., (1, 20), (2, 2), (2, 4). (2, 20), (3, 3), (3, 6), . (3, 18),
(4, 4), (4, 8), . (4, 20), (5, 5), (5, 10), (5, 15), (5, 20), (6, 6), (6, 12), (6, 18), (7. 7),
(7, 14), (8, 8), (8, 16), (9, 9), (9, 18), (10, 10), (10, 20), (11, 11), (12, 12)


⇒ (y, x) ∈ R V (x, y) ∈ R
(x, y) ∈ R ⇒ 2x = 3y and (y, x) ∈ R ⇒ 3x = 2y
Which holds only for (0, 0)
Which does not belongs to R.
∴ Value of n = 0
f is increasing function
x < 5x < 7x

f (x) < f (5x) < f (7x)
->
Given f (k) =
Case I : If x is even then g (x) = x . (i)
Case II : If x is odd then g (x + 1) = x + 1 . (ii)
From (i) & (ii), g (x) = x, when x is even
So total no. of functions = 105 × 1 = 105
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Maths Relations and Functions 2025
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