7. Minimise and Maximise Z = 5x + 10 y subject to x + 2y ≤ 120, x + y ≥ 60, x – 2y ≥ 0, x, y ≥ 0.
7. Minimise and Maximise Z = 5x + 10 y subject to x + 2y ≤ 120, x + y ≥ 60, x – 2y ≥ 0, x, y ≥ 0.
Minimize and Maximise
Subject to
The corresponding equation of the given inequalities are
The graph of the inequalities in shown.

The shaded founded region ABCD is the feasible region with the corner points
The value of Z a these corner points are

The minimum value of Z is 300 at (60,0) and the maximum
Similar Questions for you
= -8 (-3 + k)
For inconsistent
. (ii)
by using property
Adding (i) and (ii) we get 2l =
Given 2x + y – z = 3 . (i)
x – y – z = α . (ii)
3x + 3y + βz = 3 . (iii)
(i) x 2 – (ii) – (iii) – (1 + β) z = 3 - α
For infinite solution 1 + β
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Maths Ncert Solutions class 12th 2026
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering