78. The smallest and largest no. between 200 and 400 which are divisible by 7 is

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    78. 7282005740014605643550491Smallest =2004+7=203Largest =4001=399

    So we can form an A.P. 203,203+7, …., 399-7, 399

    So, i.e. a = 203 and d = 7 

    l = 399

    a+(x1)d=399

    203+(x1)7=399

    (x1)7=399203

    x1=1967

    x=28+1

    x=29

    Sum of the 29 number of the AP = Required sum = η2[a+l)

    =292[203+399]

    =292×602

    = 8729.

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A
alok kumar singh

First term = a

Common difference = d

Given: a + 5d = 2        . (1)

Product (P) = (a1a5a4) = a (a + 4d) (a + 3d)

Using (1)

P = (2 – 5d) (2 – d) (2 – 2d)

-> = (2 – 5d) (2 –d) (– 2) + (2 – 5d) (2 – 2d) (– 1) + (– 5) (2 – d) (2 – 2d)

d P d d = –2 [ (d – 2) (5d – 2) + (d – 1) (5d – 2) + (d – 1) (5d – 2) + 5 (d – 1) (d – 2)]

= –2 [15d2 – 34d + 16]

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A
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a, ar, ar2, ….ar63

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A
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S20 = 2 0 2 [2a + 19d] = 790

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A
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3, 7, 11, 15, 19, 23, 27, . 403 = AP1

2, 5, 8, 11, 14, 17, 20, 23, . 401 = AP2

so common terms A.P.

11, 23, 35, ., 395

->395 = 11 + (n – 1) 12

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32 = n – 1

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3, a, b, c are in A.P.

a – 3 = b – a                                                 (common diff.)

2a = b + 3

and 3, a – 1, b + 1 are in G.P.

a 1 3 = b + 1 a 1              

a2 + 1 – 2a = 3b + 3

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