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A box contains 3 orange balls, 3 green balls, and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is

0 8 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago

    This is a Objective Type Questions as classified in NCERT Exemplar

    Sol:

    Probability  of  drawing  2  green  and  1  blue  balls                 =P(G).P(G).P(B)+P(G).P(B).P(G)+P(B).P(G).P(G)                 =38.27.26+38.27.26+28.37.26=12336+12336+12336=36336=328Hence,  the  correct  option  is  (a).

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